E
Editor
Sep 18, 2022
If $\alpha, \beta\:and\:\gamma$ are the measures of angles of a triangle and a,b and c are the lengths of opposite these angles, then according to law of sine
Difficulty: Easy
A:
$a^{2}=b^{2}+c^{2}-2bc\sin\alpha$
B:
$a^{2}=b^{2}+c^{2}-2bc\cos\alpha$
C:
$c^{2}=a^{2}+b^{2}-2ab\sin\alpha$
D:
$\frac{a}{\sin\alpha}=\frac{b}{\sin\alpha}=\frac{c}{\sin\alpha}
ID: 63273db9ca83163ac3a1099b