How much ice will melt by 5000 J of heat? Latent heat of fusion of ice = $336000 J 〖kg〗^{-1}$. (149 g )
Difficulty: Easy
Solution: Amount of heat required to melt ice = 50000J
Latent heat of fusion of ice = = $336000 J 〖kg〗^{-1}$
Amount of ice = m =?
$ \triangle Q_{f}$= $m H_{f}$
Or m = $\frac{(\triangle Q_{f} )}{(H_{f})}$
m =$\frac{50000}{336000}$ = 0.1488 kg
= $ 0.1488 \times 1000$ =$\frac{1488}{1000} \times $1000 = $148.8 g \approx 149 g$
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