Find the acceleration due to gravity on the surface of Mars. The mass of Mars is $6.42 \times 10^{23}$ kg and its radius is 3370 km.
Difficulty: Medium
Solution:
Mass of Mars = $M_{m}$ = $6.42\times 1023$ kg
Radius of Mars =$R_{m}$ = 3370 km = $3370 \times 1000$ m = $3.37 \times 10^{8} m$
Acceleration due to gravity of the surface of Mars = $g_{m}$ =?
G =$\frac{6.673*10^{-11} * 6.42*10^{23}}{11.357}$
gm =$\frac{G M_{m}}{〖R〗^{2}_{m}}$
or gm = $6.673 \times 10^{-11} \times$ $(6.42 \times 10^{23})(3.37 \times 10^{6})^{2}$
=$\frac{(6.673 \times 10^{(-11)}\times 6.42 \times 10^{23})}{11.357}$
=$\frac{42.84}{11.357}$ = 3.77 $m^{-2}$
Sponsored Ads