(i) P.E. at its maximum height (ii) K.E. when it hits the ground
E
Editor
Jun 21, 2022
A 500 g stone is thrown up with a velocity of $15 ms^{-1}$. Find its (i) P.E. at its maximum height (ii) K.E. when it hits the ground (56.25 J, 56.25 J)
Solution:
Mass of stone = m = 500 g = $\frac{500}{1000}$ kg = 0.5 kg