25:[["$","title","0",{"children":"A force is acting on a body making an angle of 30⁰ with the horizontal. "}],["$","meta","1",{"name":"description","content":"Class 9 FBISE Physics - Turning effect of forces - A force is acting on a body making an angle of 30⁰ with the horizontal. "}],["$","meta","2",{"name":"author","content":"Editor"}],["$","link","3",{"rel":"manifest","href":"https://classnotes.xyz/site.webmanifest","crossOrigin":"$undefined"}],["$","meta","4",{"name":"keywords","content":"Physics, Turning effect of forces"}],["$","meta","5",{"name":"creator","content":"classnotes"}],["$","meta","6",{"name":"robots","content":"index,follow"}],["$","meta","7",{"name":"application/ld+json","content":"{\"@context\":\"https://schema.org\",\"@type\":\"QAPage\",\"mainEntity\":{\"@type\":\"Question\",\"name\":\"

A force is acting on a body making an angle of 30⁰ with the horizontal. The horizontal component of the force is 20 N. Find the force. (23.1 N)

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Solution:

\\n

Angle θ = 30⁰ (with x-axis)

\\n

Horizontal component of force $F_{x}$ = 20 N

\\n

Force F = ?

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$F_{x}$ = F cos θ

\\n

20 N = F cos 30⁰

\\n

20 N = $F \\\\times 0.866$ (˙.˙ cos 30⁰ = 0.866)

\\n

F =$\\\\frac{ 20 N}{0.866}$= 23.09

\\n

F = 23.1 N

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