How much heat is required to change 100g of water at 100°C into steam

Question

How much heat is required to change 100g of water at 100°C into steam? (Latent heat of vaporization of water is $2.26 imes 〖10〗^{6} J〖kg〗^{-1}$. $(2.26 imes 〖10〗^{5}J)$

Accepted Answer

Solution: Mass of water = m = 100 g = $\frac{100}{1000}$ = 0.1 kg
Latent heat of vaporization of water = $H_{v}$ = $2.26 imes 10^{6} Jkg^{-1}$
Heat required = $ riangle Q_{v}$= ?
$ riangle Q_{v}= mH_{v}$
$ riangle Q_{v}$= $0.1 imes 2.26 imes 10^{6}$ = $0.226 imes 10^{6}$ = $\frac{226}{1000} imes 10^{6}$
= $2.26 imes 10^{-1} imes 10^{6}$ = $2.26 imes 10^{5}$J