A student presses her palm by her thumb with a force of 75 N. How much would the pressure under her thumb have a contact area of $1.5 cm^{2}$?
$(5\times105 Nm^{-2})$
Difficulty: Easy
Solution:
Force = F = 75 N
Contact Area A = $1.5 cm^{2}$ = $1.5 \times \frac{1}{100}\times\frac{1}{100} m^{2}$ = $1.5 \times 10^{-4} m^{2}$
Pressure under the thumb = P =?
P =$\frac{F}{A}$
P =$\frac{75}{(1.5 × 10^(-4))}$ = $\frac{75}{1.5 \times 10^{-4}}$= $5 \times 10^{5} Nm^{-2}$
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