A solid block of wood of density

Question

A solid block of wood of density $0.6 gcm^{-3}$ weighs 3.06 N in air. Determine (a) volume of the block (b) the volume of the block immersed when placed freely in a liquid of density 0.9 $gcm^{-3}$ ? $(510 cm_{3} , 340 cm_{3})$

Accepted Answer

Solution:

(a) Density of wood = D = $0.6 gcm^{-3}$

Weight of the wooden block = w= 3.06 N

Since w = mg or m $=\frac{w}{g}=\frac{3.06}{10} = 0.306 kg = 306$ g

Density of liquid D = $0.9 gcm^{-3}$

(i) The volume of the block V =?

(ii) The volume of the block immersed in a liquid V =?

Density $=\frac{Mass}{Volume}$

Volume $=\frac{Mass}{Density}$

V =$\frac{ 306}{(0.6)} = 510 cm_{3}$

(b) Volume =$\frac{Mass}{Density}$

V =$\frac{306}{(0.9)} = 340 cm_{3}$