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Rewrite the following In Standard form. (Scientific notation)
(a) $1168\times 10^{-27}$ (b) $32\times 10^{5}$
(C) $725 \times 10 kg^{-5}$ (d) $0.02\times 10^{-8}$
{(a) $1.168\times10^{-24}$ (b) $3.2\times10^{6}$ (c) $7.25g (d) 2\times10^{-10}$
Solution:
(a) $1168 \times10^{-27} = 1.168 \times 10^{3} \times 10^{-27} = 1.168 \times 10^{-24}$
(b) $32 \times 10^{5} = 3.2 \times 10^{1} \times 10^{5} = 3.2 \times10^{6}$
(C) $725 \times 10^{-5} kg=7.25\times 10^{2} \times 10^{-5} kg = 7.25 \times 10^{-3}$ kg
As $(10^{-3} kg = 1g)$, therefore
$7.25 \times 10^{-3} kg = 7.25g$
(d) $0.02 \times 10^{-8} = 2\times 10^{-2}\times 10^{-8} = 2 \times 10^{-10}$