25:[["$","title","0",{"children":"A screw gauge has 50 divisions on its circular sale. "}],["$","meta","1",{"name":"description","content":"Class 9 FBISE Physics - Physical Quantities and Measurement - A screw gauge has 50 divisions on its circular sale. "}],["$","meta","2",{"name":"author","content":"Editor"}],["$","link","3",{"rel":"manifest","href":"https://classnotes.xyz/site.webmanifest","crossOrigin":"$undefined"}],["$","meta","4",{"name":"keywords","content":"Physics, Physical Quantities and Measurement"}],["$","meta","5",{"name":"creator","content":"classnotes"}],["$","meta","6",{"name":"robots","content":"index,follow"}],["$","meta","7",{"name":"application/ld+json","content":"{\"@context\":\"https://schema.org\",\"@type\":\"QAPage\",\"mainEntity\":{\"@type\":\"Question\",\"name\":\"

A screw gauge has 50 divisions on its circular sale. The pitch of the screw gauge is 0.5 mm. What is its least count? (0.001 cm)

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Solution:

\\n

Number Of divisions on the circular scale = 50

\\n

Pitch of screw gauge = 0.5 mm

\\n

Least count Of screw gauge L.C. =?

\\n

Least count = Pitch / Number Of division on the circular scale

\\n

Least count = $\\\\frac{0.5mm}{50}$
= 0.01 mm = $0.01\\\\times \\\\frac{1}{10}$cm
Least count = 0.001 cm

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