Find the acceleration due to gravity on the surface of Mars.

Question

Find the acceleration due to gravity on the surface of Mars. The mass of Mars is $6.42 imes 10^{23}$ kg and its radius is 3370 km.

Accepted Answer

Solution:

Mass of Mars = $M_{m}$ = $6.42 imes 1023$ kg

Radius of Mars =$R_{m}$ = 3370 km = $3370 imes 1000$ m = $3.37 imes 10^{8} m$

Acceleration due to gravity of the surface of Mars = $g_{m}$ =?

G =$\frac{6.673*10^{-11} * 6.42*10^{23}}{11.357}$

gm =$\frac{G M_{m}}{〖R〗^{2}_{m}}$

or gm = $6.673 imes 10^{-11} imes$ $(6.42 imes 10^{23})(3.37 imes 10^{6})^{2}$

=$\frac{(6.673 imes 10^{(-11)} imes 6.42 imes 10^{23})}{11.357}$

=$\frac{42.84}{11.357}$ = 3.77 $m^{-2}$