Two masses 26 kg and 24 kg are attached to the ends of a string which passes over a frictionless pulley.

Question

Two masses 26 kg and 24 kg are attached to the ends of a string which passes over a frictionless pulley. 26 kg is lying over a smooth horizontal table. 24 N mass is moving vertically downward. Find the tension in the string and the acceleration in the bodies. (125 N, 4.8 $ms^{-2}$)

Accepted Answer

Solution:

m1 = 24 kg and m2 = 26 kg

Tension T =?

Acceleration a =?

T =$\frac{(m_1 m_2)}{(m_1+ m_2 )}g$

T = $\frac{(24 ×26)}{(24 + 26)} imes$ 10

T = $\frac{6240}{50}$

T = 124.8 ≈ 125 N

a =$\frac{(m_1)}{(m_1+ m_2 )}$ g

a = $\frac{24}{(24 + 26)} imes10$

a = $\frac{24}{50} imes10$

a = 4.8 $ms^{-2}$