Partial… | NUST Entrance Test Mathematics

If $\frac{4x}{(x-1)(x+1)}=\frac{A}{x-1}+\frac{B}{x+1}$ then the values of $A$ and $B$ are

Difficulty: Easy

A:

2 and 2

B:

1 and $-1$

C:

2 and $-2$

D:

None of these

\frac{1}{x(x+1)}=\frac{A}{x+1}+\frac{B}{x}$ then $A+B=

Difficulty: Easy

A:

0

B:

1

C:

2

D:

-2

$\frac{5x-11}{2x^{2}+x-6}$=

Difficulty: Hard

A:

\frac{3}{x+2}-\frac{1}{2x-3}

B:

\frac{1}{x+2}-\frac{3}{2x-3}

C:

\frac{4}{x+2}+\frac{7}{2x-3}

D:

None

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