When $\rm{CH_{2} =CH_{2}}$ reacts with a halogen acid, the product formed is

E

Editor

Sep 18, 2022

When $\rm{CH_{2} =CH_{2}}$ reacts with a halogen acid, the product formed is

Difficulty: Easy

A:

Alkane

B:

Alkyl halide

C:

Alkyl

D:

Alkene

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ID: 63273dbcca83163ac3a158b3