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Two identical conducting spheres A and B carry equal charge Q. They are separated by a distance much larger than their diameters. A third identical conducting sphere C carries charge 2Q. Sphere C is first touched to A, then to B, and finally removed. As a result, the electrostatic force between A and B, which was originally F, becomes
Difficulty: Easy
A: 
$\rm{\frac{F}{2}}$
B: 
$\rm{\frac{15F}{8}}$
C: 
$\rm{\frac{5F}{7}}$
D: 
$\rm{\frac{2F}{5}}$
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