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What will be the value of $\beta$ for a solid for which $\alpha$ has a value of $2 \times 10^{-5} \ K^{-1}$?
$2 \times 10^{-5} \ K^{-1}$
$6 \times 10^{-5} \ K^{-1}$
$8 \times 10^{-15} \ K^{-1}$
$8 \times 10^{-5} \ K^{-1}$