The term independent of x in the expansion $(x^{2}+\frac{1}{x})^{12}$

E

Editor

Sep 18, 2022

The term independent of x in the expansion $(x^{2}+\frac{1}{x})^{12}$

Difficulty: Easy

A:

295

B:

495

C:

395

D:

722

ID: 63273db9ca83163ac3a1177b