Editor
The nth term of the sequence $\frac{(4)^{2}}{3},\frac{(7)^{2}}{3},\frac{(10)^{2}}{3}$....is
Difficulty: Easy
A: 
$\frac{(3n+1)^{3}}{3}$
B: 
$\frac{3n^{2}+1}{3}$
C: 
$\frac{(3n+1)^{2}}{3}$
D: 
$\frac{(3n-1)^{2}}{3}$
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