$(x-6)^{2}+(y+5)^{2}=16$<br/><br/>In the $xy$-plane, the graph of the equation above is a circle. Point $P$ is on the circle and has coordinates $(10,-5)$. If $\overline{PQ}$ is a diameter of the circle, what are the coordinates of point $Q$ ?

MM

Mashaal Masha

Mar 01, 2024

$(x-6)^{2}+(y+5)^{2}=16$In the $xy$-plane, the graph of the equation above is a circle. Point $P$ is on the circle and has coordinates $(10,-5)$. If $\overline{PQ}$ is a diameter of the circle, what are the coordinates of point $Q$ ?

Difficulty: Hard

A:

$(2,-5)$

B:

$(6,-1)$

C:

\((6,-5)\)

D:

$(6,-9)$

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ID: 65e23b5ee130c9f9159a13b3