$(x-6)^{2}+(y+5)^{2}=16$ In the $xy$-plane,… | ClassNotes
MM
Mashaal Masha
Mar 01, 2024
$(x-6)^{2}+(y+5)^{2}=16$
In the $xy$-plane, the graph of the equation above is a circle. Point $P$ is on the circle and has coordinates $(10,-5)$. If $\overline{PQ}$ is a diameter of the circle, what are the coordinates of point $Q$ ?
