<h5>$$F(x)=\frac{9}{5}(x-273.15)+32$$<br/><br/>The function $F$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. If a temperature increased by $2.10$ kelvins, by how much did the temperature increase, in degrees Fahrenheit?</h5>

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Mashaal Masha

$$F(x)=\frac{9}{5}(x-273.15)+32$$

The function $F$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. If a temperature increased by $2.10$ kelvins, by how much did the temperature increase, in degrees Fahrenheit?

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Mashaal Masha

$$F(x)=\frac{9}{5}(x-273.15)+32$$The function $F$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. If a temperature increased by $2.10$ kelvins, by how much did the temperature increase, in degrees Fahrenheit?

$$F(x)=\frac{9}{5}(x-273.15)+32$$

The function $F$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. If a temperature increased by $2.10$ kelvins, by how much did the temperature increase, in degrees Fahrenheit?