MM
Mashaal Masha
Feb 19, 2024
$$57x^{2}+(57b+a)x+ab=0$$
In the given equation, $a$ and $b$ are positive constants. The product of the solutions to the given equation is $kab$, where $k$ is a constant. What is the value of $k$?
Difficulty: Hard
A:
$\frac{1}{57}$
B:
$\frac{1}{19}$
C:
$1$
D:
$57$
ID: 65d33867dbc6daab1ce197e9