<h5>$\dfrac{2}{x-2}+\dfrac{3}{x+5}=\dfrac{rx+t}{(x-2)(x+5)}$<br /><br />The equation above is true for all $x&gt;2$, where $r$ and $t$ are positive constants. What is the value of $rt$?</h5>

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$\dfrac{2}{x-2}+\dfrac{3}{x+5}=\dfrac{rx+t}{(x-2)(x+5)}$

The equation above is true for all $x>2$, where $r$ and $t$ are positive constants. What is the value of $rt$?

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Mashaal Masha

$\dfrac{2}{x-2}+\dfrac{3}{x+5}=\dfrac{rx+t}{(x-2)(x+5)}$The equation above is true for all $x>2$, where $r$ and $t$ are positive constants. What is the value of $rt$?

$\dfrac{2}{x-2}+\dfrac{3}{x+5}=\dfrac{rx+t}{(x-2)(x+5)}$

The equation above is true for all $x>2$, where $r$ and $t$ are positive constants. What is the value of $rt$?