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$64x^{2}+bx+25=0$ In the given equation,… | ClassNotes
MM
Mashaal Masha
Feb 24, 2024
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$$64x^{2}+bx+25=0$$
In the given equation, $b$ is a constant. For which of the following values of $b$ will the equation have more than one real solution?
Difficulty: Hard
A:
$-91$
B:
$-80$
C:
5
D:
40
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ID: 65d9d9b772be60754a54e110