$$64x^{2}+bx+25=0$$<br/><br/>In the given equation, $b$ is a constant. For which of the following values of $b$ will the equation have more than one real solution?

MM

Mashaal Masha

Feb 24, 2024

$$64x^{2}+bx+25=0$$In the given equation, $b$ is a constant. For which of the following values of $b$ will the equation have more than one real solution?

Difficulty: Hard

A:

$-91$

B:

$-80$

C:

5

D:

40

View Solution Steps

ID: 65d9d9b772be60754a54e110