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$x^{2}=\theta x+y$ $ $y=-6x+36$ $ A solution… | ClassNotes
MM
Mashaal Masha
Feb 24, 2024
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$x^{2}=6x+y$
$y=-6x+36$
A solution to the given system of equations is $(x,y)$. Which of the following is a possible value of $xy$?
Difficulty: Medium
A:
$0$
B:
$6$
C:
$12$
D:
$36$
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ID: 65d979f894fbe38fff11e759
