Editor
Editor
 Sep 18, 2022
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$\int (\sqrt{x}+1)^{2}$ equals:
Difficulty: Easy
A: 
$\frac{1}{2} \sqrt{x}+x+c$
B: 
$\frac{1}{2}x^{2}+\frac{4}{3}x^{\frac{3}{2}}+x+c$
C: 
$\frac{1}{2}\sqrt{2}+x^{2}+c$
D: 
$\sqrt{x}+\frac{3}{2}x^{2}+c$
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NETNUST Entry TestMathematicsIntegration