E
Editor
Sep 18, 2022
In $\triangleABC$ if $\beta=90^{\circ}$, then according to law of cosine the value of the square of the side b is defined as:
Difficulty: Easy
A:
$b^{2}=a^{2}+b^{2}-2ab$
B:
$b^{2}=b^{2}+b^{2}-2bc\cos\beta$
C:
$b^{2}=a^{2}+c^{2}$
D:
$b^{2}=a^{2}+c^{2}+2ac\cos\beta$
ID: 63273db9ca83163ac3a119bb