In triangle ABC $a=\sqrt{3}-1$ $b=\sqrt{3}+1$ and $\beta=60^{\circ}$ then the third side of the triangle is | ClassNotes | Ace Your Exams

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Sep 18, 2022

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In triangle ABC $a=\sqrt{3}-1$ $b=\sqrt{3}+1$ and $\beta=60^{\circ}$ then the third side of the triangle is

Difficulty: Easy

A:

2.45

B:

7.46

C:

8

D:

2.82

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NET NUST Entry Test Mathematics Fundamentals of Trignometry