E
Editor
Sep 18, 2022
If $z_{1}=a_{1}+\iota b_{1}$, and $z_{2}=a_{2}+\iota b_{2}$ then $z_{1}+z_{2}$=
Difficulty: Hard
A:
$(a_{1}a_{2}+b_{1}b_{2})$
B:
$(a_{1}+a_{2}\:b_{1}+b_{2})$
C:
$(a_{1}a_{2}-b_{1}b_{2})$
D:
$(a_{1}a_{2}\:b_{1}b_{2})$
ID: 63273dbaca83163ac3a1219b