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If $\sin\theta=\frac{12}{13}$, and $\sin\theta>0$, then $\tan\theta+$
Difficulty: Easy
A: 
$\frac{2}{5}$
B: 
$-\frac{12}{13}$
C: 
$\frac{13}{5}$
D: 
$\frac{12}{5}$
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