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If $\omega=\frac{-1+\sqrt{3}\iota}{2}$ then $\omega^{3}$=
Difficulty: Easy
A: 
1
B: 
$-\iota$
C: 
$\frac{-1-\sqrt{3}\iota}{2}$
D: 
$\frac{1-\sqrt{3}\iota}{2}$
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