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Sep 18, 2022
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If $\omega=\frac{-1+\sqrt{3}\iota}{2}$ then $\omega^{3}$=
Difficulty: Easy
A:
1
B:
$-\iota$
C:
$\frac{-1-\sqrt{3}\iota}{2}$
D:
$\frac{1-\sqrt{3}\iota}{2}$
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ID: 63273dbaca83163ac3a127d1