E
Editor
Sep 18, 2022
If $\omega=\frac{-1+\sqrt{3}\iota}{2}$ then $\omega^{3}$=
Difficulty: Easy
A:
1
B:
$-\iota$
C:
$\frac{-1-\sqrt{3}\iota}{2}$
D:
$\frac{1-\sqrt{3}\iota}{2}$
ID: 63273dbaca83163ac3a127d1