E
Editor
Sep 18, 2022
If $f(x)=\sqrt{x+1}$ and $g(x)=\frac{1}{x^{2}}$ then fof(x)=
Difficulty: Easy
A:
$\frac{1}{x+1}$
B:
$\frac{3(x-1)}{4-x}$
C:
$\frac{3}{2x}$
D:
$\frac{1}{{\sqrt{\sqrt{x+1}+1}}}$
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ID: 63273db8ca83163ac3a106cb