Editor
Editor
 Sep 18, 2022
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If $f(x)=\frac{2x}{x-1}$ then $f^{3}(x)$=
Difficulty: Easy
A: 
$\frac{3x}{(x-1)^{3}}$
B: 
$\frac{8x}{3x-1}$
C: 
$\frac{8x^{3}}{x-1}$
D: 
$\frac{8x}{2x+3}$
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NETNUST Entry TestMathematicsFunctions and Limits