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If $f(x)=3x^{3}+7$, then $f^{-1}(x)=$
Difficulty: Easy
A: 
$(\frac{7x}{3})^{\frac{1}{3}}$
B: 
$(\frac{7}{3}x)^{\frac{1}{3}}$
C: 
$(\frac{x-7}{3})^{\frac{1}{3}}$
D: 
$(\frac{3x-7}{3})^{\frac{1}{3}}$
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