E
Editor
Sep 18, 2022
If $f(x)=(1+\frac{1}{x})(1+\frac{1}{x^{2}})$ then f'(x)=
Difficulty: Easy
A:
$\frac{1+x}{\sqrt{1+x^{2}}.\sqrt{1+\frac{1}{x}}}$
B:
$\frac{x}{\sqrt{x^{2}+1}.\sqrt{1-x^{2}}}$
C:
$(1+x^{-2})(1-x^{-3})$
D:
None
ID: 63273db8ca83163ac3a10263