Editor
Editor
 Sep 18, 2022
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If $f(x)=(1+\frac{1}{x})(1+\frac{1}{x^{2}})$ then f'(x)=
Difficulty: Easy
A: 
$\frac{1+x}{\sqrt{1+x^{2}}.\sqrt{1+\frac{1}{x}}}$
B: 
$\frac{x}{\sqrt{x^{2}+1}.\sqrt{1-x^{2}}}$
C: 
$(1+x^{-2})(1-x^{-3})$
D: 
None
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NETNUST Entry TestMathematicsDifferentiation