If $\alpha, \beta\: and\: \gamma$ are the corresponding angles of the sides a, b and c respectively in an oblique triangle, then according to law of cosins, the value of the square of the side a is

Question

Accepted Answer

$b^{2}=b^{2}+c^{2}-2bc\cos\alpha$

Answer

$a^{2}=a^{2}+b^{2}-2ab\cos\alpha$

Answer

$a^{2}=a^{2}+b^{2}-ab\cos\alpha$

Answer

$b^{2}=b^{2}+c^{2}-2ab\cos\alpha$