Editor
Editor
 Sep 18, 2022
0
If a is the first term, d is common difference, then the sum of nth term of the series $S_{n}$=
Difficulty: Easy
A: 
n/a[a+(n-1)d]
B: 
a+(n-1)d
C: 
n/2[2a+(n-1)d]
D: 
n/a[2a+(n-1)d]
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NETNUST Entry TestMathematicsSequence and Series