E
Editor
Sep 18, 2022
If $A=\begin{bmatrix}\iota & 0 \\1 & -\iota \end{bmatrix}$ then $A^{2}$=
Difficulty: Easy
A:
$\begin{bmatrix}\iota^{2} & 0 \\0 & \iota^{2} \end{bmatrix}$
B:
$\begin{bmatrix}\iota^{2} & 0 \\0 & -\iota^{2} \end{bmatrix}$
C:
$\begin{bmatrix}\iota^{2} & 0 \\1 & \iota^{2} \end{bmatrix}$
D:
$\begin{bmatrix}-\iota^{2} & 0 \\0 & -\iota^{2} \end{bmatrix}$
ID: 63273dbaca83163ac3a11d0f