E
Editor
Sep 18, 2022
If $A=\begin{bmatrix}7&49\\14 & 56\\42 & 35 \end{bmatrix}$ then 2A/7=
Difficulty: Easy
A:
$\begin{bmatrix}2&7\\4 & 8\\12 & 5 \end{bmatrix}$
B:
$\begin{bmatrix}1&7\\2 & 8\\6 & 5 \end{bmatrix}$
C:
$\begin{bmatrix}14&98\\28 & 112\\84 & 70 \end{bmatrix}$
D:
$\begin{bmatrix}2&14\\4 & 16\\12 & 10 \end{bmatrix}$
ID: 63273dbaca83163ac3a11c37