Editor
If A=3/2, B=1 and C=1/2 then $\int \frac{2x^{2}}{(x-1)^{2}(x+1)} dx$ is equal to:
Difficulty: Easy
A: 
$\frac{3}{2}ln(x-1)^{2}+\frac{1}{2}ln|x+1|+ln|x+1|$
B: 
$\frac{3}{2}ln(x-1)+\frac{1}{2}ln|x+1|-ln|x+1|$
C: 
$\frac{3}{2}ln(x-1)^{2}+\frac{1}{2}ln|x+1|-\frac{1}{x-1}$
D: 
$\frac{3}{2}ln(x-1)+\frac{1}{2}ln|x+1|-\frac{1}{x-1}$
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