$\frac{1}{x(x+1)}=\frac{A}{x+1}+\frac{B}{x}$ then $A+B=$

Question

$\frac{1}{x(x+1)}=\frac{A}{x+1}+\frac{B}{x}$ then $A+B=$

Accepted Answer

0

Answer

1

Answer

2

Answer

-2