E
Editor
Sep 18, 2022
For any positive integer $n,1+\frac{1}{2}+\frac{1}{4}+.....+\frac{1}{2^{n-1}}=$
Difficulty: Easy
A:
$2[1-\frac{1}{2^{n}}$
B:
$[1-\frac{1}{2^{n}}$
C:
$n[1-\frac{1}{2^{n}}$
D:
$2[1+\frac{1}{2^{n}}$
Report issue
ID: 63273db9ca83163ac3a1162b