E
Editor
Sep 18, 2022
Determinant of $\begin{bmatrix}\alpha& \beta+\gamma& 1 \\\beta & \gamma+\alpha & 1\\\gamma&\alpha+\beta&1 \end{bmatrix}$
Difficulty: Hard
A:
0
B:
$(\alpha+\beta+\gamma)$
C:
$(\alpha+\beta+\gamma)(1-\alpha)$
D:
$(\alpha+\beta+\gamma)(\alpha-\beta)(\alpha-\gamma)$
ID: 63273dbaca83163ac3a11dab