QUESTION 2 PART 2 FROM EX:1.3 IS INCORRECT IN NOTES,THIS IS NOT SIMPLE WAY QUESTION,FIRST WE TAKE COMMON X FROM NUMERATOR AND DENOMENATOR THEN CANCEL OUT X ,AND PUT LIMIT IN REMAINIG FUNCTION.PLEASE CORRECT THIS.

Organizer
on October 22, 2019 at 12:55 am

Hi, the answer remains the same in both cases because the limit of x only approaches 1, which means its square or cube will remain 1. Therefore, this is also a correct approach.

Faizan tahir
on January 6, 2020 at 9:38 am

Hello sir sorry to interrupt but you solved the wrong question.
Question mentioned in book is as under:
Limit approaches to 0 not 1
Plz correct it

Faizan tahir
on January 6, 2020 at 9:43 am

And question 3 part 2 in ex 1.3
1 degree is equal to pie / 180 NOT 10 DEGREE

Organizer
on January 7, 2020 at 1:41 am

Thank you for pointing this out Faizan. We will correct this when we update our notes soon.

QUESTION 2 PART 2 FROM EX:1.3 IS INCORRECT IN NOTES,THIS IS NOT SIMPLE WAY QUESTION,FIRST WE TAKE COMMON X FROM NUMERATOR AND DENOMENATOR THEN CANCEL OUT X ,AND PUT LIMIT IN REMAINIG FUNCTION.PLEASE CORRECT THIS.

Hi, the answer remains the same in both cases because the limit of x only approaches 1, which means its square or cube will remain 1. Therefore, this is also a correct approach.

Hello sir sorry to interrupt but you solved the wrong question.

Question mentioned in book is as under:

Limit approaches to 0 not 1

Plz correct it

And question 3 part 2 in ex 1.3

1 degree is equal to pie / 180 NOT 10 DEGREE

Thank you for pointing this out Faizan. We will correct this when we update our notes soon.