QUESTION 2 PART 2 FROM EX:1.3 IS INCORRECT IN NOTES,THIS IS NOT SIMPLE WAY QUESTION,FIRST WE TAKE COMMON X FROM NUMERATOR AND DENOMENATOR THEN CANCEL OUT X ,AND PUT LIMIT IN REMAINIG FUNCTION.PLEASE CORRECT THIS.
Organizer
on October 22, 2019 at 12:55 am
Hi, the answer remains the same in both cases because the limit of x only approaches 1, which means its square or cube will remain 1. Therefore, this is also a correct approach.
QUESTION 2 PART 2 FROM EX:1.3 IS INCORRECT IN NOTES,THIS IS NOT SIMPLE WAY QUESTION,FIRST WE TAKE COMMON X FROM NUMERATOR AND DENOMENATOR THEN CANCEL OUT X ,AND PUT LIMIT IN REMAINIG FUNCTION.PLEASE CORRECT THIS.
Hi, the answer remains the same in both cases because the limit of x only approaches 1, which means its square or cube will remain 1. Therefore, this is also a correct approach.